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1Z1-051 - Oracle Database 11g SQL Fundamentals I - BrainDump Information

Vendor Name : Oracle
Exam Code : 1Z1-051
Exam Name : Oracle Database 11g SQL Fundamentals I
Questions and Answers : 254 Q & A
Updated On : February 16, 2018
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Note: Answers are below each question.
Samples are taken from full version.

1Z1-051


QUESTION: 238

You need to perform these tasks:

  • Create and assign a MANAGER role to Blake and Clark

  • Grant CREATE TABLE and CREATE VIEW privileges to Blake and Clark Which set of SQL statements achieves the desired results?

  • CREATE ROLE manager; GRANT create table, create view TO manager;

    GRANT manager TO BLAKE,CLARK;

  • CREATE ROLE manager; GRANT create table, create voew TO manager;

GRANT manager ROLE TO BLAKE,CLARK;

GRANT create table, create voew TO BLAKE CLARK;

***MISSING***


A. GRANT manager ROLE TO BLAKE,CLARK;


Answer: A


Explanation:

Result of commands:

QUESTION: 239

Which two are true about aggregate functions? (Choose two.)


  1. You can use aggregate functions in any clause of a SELECT statement.

  2. You can use aggregate functions only in the column list of the select clause and in the WHERE

    clause of a SELECT statement.

  3. You can mix single row columns with aggregate functions in the column list of a SELECT statement by grouping on the single row columns.

  4. You can pass column names, expressions, constants, or functions as parameter to an aggregate function.

  5. You can use aggregate functions on a table, only by grouping the whole table as one single group.

  6. You cannot group the rows of a table by more than one column while using aggregate functions.


Answer: A, D

Explanation: QUESTION: 240

Which statement correctly describes SQL and /SQL*Plus?


  1. Both SQL and /SQL*plus allow manipulation of values in the database.

  2. /SQL*Plus recognizes SQL statements and sends them to the server; SQL is the Oracle proprietary interface for executing SQL statements.

  3. /SQL*Plus is a language for communicating with the Oracle server to access data; SQL recognizes SQL statements and sends them to the server.

  4. SQL manipulates data and table definitions in the database; /SQL*Plus does not allow manipulation of values in the database.


Answer: A


QUESTION: 241

Examine the structure of the STUDENTS table: STUDENT_ID NUMBER NOT NULL, Primary Key

STUDENT_NAME VARCHAR2(30) COURSE_ID VARCHAR2(10) NOT NULL MARKS NUMBER

START_DATE DATE FINISH_DATE DATE

You need to create a report of the 10 students who achieved the highest ranking in the course INT SQL and who completed the course in the year 1999. Which SQL statement accomplishes this task?


  1. SELECT student_ id, marks, ROWNUM "Rank" FROM students WHERE ROWNUM <= 10

    AND finish_date BETWEEN '01-JAN-99' AND '31-DEC-99

    AND course_id = 'INT_SQL' ORDER BY marks DESC;

  2. SELECT student_id, marks, ROWID "Rank" FROM students WHERE ROWID <= 10

    AND finish_date BETWEEN '01-JAN-99' AND '31-DEC-99' AND course_id = 'INT_SQL'

    ORDER BY marks;

  3. SELECT student_id, marks, ROWNUM "Rank" FROM (SELECT student_id, marks FROM students

    WHERE ROWNUM <= 10

    AND finish_date BETWEEN '01-JAN-99' AND '31-DEC- 99'

    AND course_id = 'INT_SQL' ORDER BY marks DESC);

  4. SELECT student_id, marks, ROWNUM "Rank” FROM (SELECT student_id, marks FROM students

    WHERE (finish_date BETWEEN ’01-JAN-99 AND ’31-DEC-99’ AND course_id = ‘INT_SQL’

    ORDER BY marks DESC) WHERE ROWNUM <= 10 ;

  5. SELECTstudent id, marks, ROWNUM “Rank” FROM(SELECT student_id, marks FROM students

ORDER BY marks) WHEREROWNUM <= 10

ANDfinish date BETWEEN ’01-JAN-99’ AND ’31-DEC-99’ ANDcourse_id = ‘INT_SQL’;


Answer: D


QUESTION: 242

The STUDENT_GRADES table has these columns: STUDENT_IDNUMBER(12) SEMESTER_ENDDATE GPANUMBER(4,3)

The registrar has asked for a report on the average grade point average (GPA), sorted from the highest grade point average to each semester, starting from the earliest date. Which statement accomplish this?


  1. SELECT student_id, semester_end, gpa FROM student_grades

    ORDER BY semester_end DESC, gpa DESC;

  2. SELECT student_id, semester_end, gpa FROM student_grades ORDER BY semester_end, gpa ASC

  3. SELECT student_id, semester_end, gpa FROM student_grades

    ORDER BY gpa DESC, semester_end ASC;

  4. SELECT student_id, semester_end, gpa FROM student_grades

ORDER BY gpa DESC, semester_end DESC; E. SELECT student_id, semester_end, gpa FROM student_grades

ORDER BY gpa DESC, semester_end ASC; F. SELECT student_id,semester_end,gpa FROM student_grades

ORDER BY semester_end,gpa DESC


Answer: F


QUESTION: 243

Which are /SQL*Plus commands? (Choose all that apply.)


  1. INSERT

  2. UPDATE

  3. SELECT

  4. DESCRIBE

  5. DELETE

  6. RENAME


Answer: D


Explanation:

Describe is a valid iSQL*Plus/ SQL*Plus command.

INSERT, UPDATE & DELETE are SQL DML Statements. A SELECT is an ANSI Standard SQL Statment not an iSQL*Plus Statement.

RENAME is a DDL Statement.


QUESTION: 244

Examine the structure of the EMPLOYEES table:

EMPLOYEE_ID NUMBER Primary Key FIRST_NAMEVARCHAR2(25) LAST_NAMEVARCHAR2(25) HIRE_DATEDATE

Which INSERT statement is valid?


  1. INSERT INTO employees (employee_id, first_name, last_name, hire_date) VALUES ( 1000,

    ‘John’, ‘Smith’, ‘01/01/01’);

  2. INSERT INTO employees(employee_id, first_name, last_name, hire_date)VALUES ( 1000,

    ‘John’, ‘Smith’, ’01 January 01’);

  3. INSERT INTO employees(employee_id, first_name, last_name, Hire_date)VALUES ( 1000,

    ‘John’, ‘Smith’, To_date(‘01/01/01’));

  4. INSERT INTO employees(employee_id, first_name, last_name, hire_date)VALUES ( 1000, ‘John’, ‘Smith’, 01-Jan-01);


Answer: D


Explanation:

It is the only statement that has a valid date; all other will result in an error. Answer A is incorrect, syntax error, invalid date format


QUESTION: 245

Examine the structure of the EMPLOYEES and NEW_EMPLOYEES tables: EMPLOYEES EMPLOYEE_IDNUMBERPrimary Key FIRST_NAMEVARCHAR2(25) LAST_NAMEVARCHAR2(25) HIRE_DATEDATE

NEW_EMPLOYEES EMPLOYEE_IDNUMBERPrimary Key NAMEVARCHAR2 (60)

Which DELETE statement is valid?


  1. DELETE FROM employeesWHERE employee_id = (SELECT employee_id FROM employees);

  2. DELETE * FROM employeesWHERE employee_id=(SELECT employee_id FROM new_employees);

  3. DELETE FROM employeesWHERE employee_id IN (SELECT employee_id FROM new_employees WHERE name = ‘Carrey’);

  4. DELETE * FROM employeesWHERE employee_id IN (SELECT employee_id FROM new_employees WHERE name = ‘Carrey’);


Answer: C


QUESTION: 246

User Mary has a view called EMP_DEPT_LOC_VU that was created based on the EMPLOYEES, DEPARTMENTS, and LOCATIONS tables. She has the privilege to create a public synonym, and would like to create a synonym for this view that can be used by all users of the database. Which SQL statement can Mary use to accomplish that task?


  1. CREATE PUBLIC SYNONYM EDL_VU ON emp_dept_loc_vu;

  2. CREATE PUBLIC SYNONYM EDL:VU FOR mary (emp_dept_loc_vu);

  3. CREATE PUBLIC SYNONYM EDL_VU FOR emp_dept_loc_vu;

  4. CREATE SYNONYM EDL_VU ON emp_dept_loc_vu FOR EACH USER;

  5. CREATE SYNONYM EDL_VU FOR EACH USER

    ON emp_dept_loc_vu;

  6. CREATE PUBLIC SYNONYM EDL_VU ON emp_dept_loc_vu FOR ALL USERS;


Answer: C


Explanation:

The general syntax to create a synonym is:

CREATE [PUBLIC] SYNONYM synonym FOR object;


QUESTION: 247

Exhibit


The COMMISSION column shows the monthly commission earned by the employee. Which two tasks would require sub queries or joins in order to be performed in a single step? (Choose two.)


  1. listing the employees who earn the same amount of commission as employee 3

  2. finding the total commission earned by the employees in department 10

  3. finding the number of employees who earn a commission that is higher than the average commission of the company

  4. listing the departments whose average commission is more that 600

  5. listing the employees who do not earn commission and who are working for department 20 in descending order of the employee ID

  6. listing the employees whose annual commission is more than 6000


Answer: A, C


QUESTION: 248

Evaluate this SQL statement: SELECT e.emp_name, d.dept_name

FROM employees e JOIN departments d USING (department_id) WHERE d.department_id NOT IN (10,40)

ORDER BY dept_name;

The statement fails when executed. Which change fixes the error?


  1. remove the ORDER BY clause

  2. remove the table alias prefix from the WHERE clause

  3. remove the table alias from the SELECT clause

  4. prefix the column in the USING clause with the table alias

  5. prefix the column in the ORDER BY clause with the table alias

  6. replace the condition”d.department_id NOT IN (10,40)”in the WHERE clause with”d.department_id <> 10 AND d.department_id <> 40”


Answer: C, E


Explanation:

Prefix the column in the ORDER BY Clause would cause the statement to succeed, assuming that the statement failed because the dept_name existed in employee & department tables.

Not C: Removing the alias from the columns in the SELECT clause would cause the Statement to fail if the columns existing in both tables.


QUESTION: 249

Examine the statement:

Create synonym emp for hr.employees; What happens when you issue the statement?


  1. An error is generated.

  2. You will have two identical tables in the HR schema with different names.

  3. You create a table called employees in the HR schema based on you EMP table.

  4. You create an alternative name for the employees table in the HR schema in your own schema.


Answer: D


QUESTION: 250

Examine the structure of the EMPLOYEES table: EMPLOYEE_IDNUMBERPrimary Key FIRST_NAMEVARCHAR2 (25) LAST_NAMEVARCHAR2 (25) HIRE_DATEDATE

Which UPDATE statement is valid?


  1. UPDATE employees SET first_name = ‘John’ SET last_name = ‘Smith’ WHERE employee_id = 180;

  2. UPDATE employees SET first_name = ‘John’, SET last_name = ‘Smoth’ WHERE employee_id = 180;

  3. UPDATE employee SET first_name = ‘John’ AND last_name = ‘Smith’ WHERE employee_id = 180;

  4. UPDATE employee

SET first_name = ‘John’, last_name = ‘Smith’ WHERE employee_id = 180;

Answer: D


QUESTION: 251

What is true about sequences?


  1. The start value of the sequence is always 1.

  2. A sequence always increments by 1.

  3. The minimum value of an ascending sequence defaults to 1.

  4. The maximum value of descending sequence defaults to 1.


Answer: C


Explanation:

The Start values of a Sequence defaults to 1 but another value may be specified with the START WITH clause


QUESTION: 252

The STUDENT_GRADES table has these columns STUDENT_IDNUMBER(12) SEMESTER_ENDDATE GPANUMBER(4,3)

Which statement finds students who have a grade point average (GPA) greater than 3.0 for the calendar year 2001?


  1. SELECT student_id, gpa FROM student_grades

    WHERE semester_end BETWEEN ’01-JAN-2001’ AND ’31-DEC-2001’ OR gpa > 3.;

  2. SELECT student_id, gpa FROM student_grades

    WHERE semester_end BETWEEN ’01-JAN-2001’ AND ’31-DEC-2001’ AND gpa gt 3.0;

  3. SELECT student_id, gpa FROM student_grades

    WHERE semester_end BETWEEN ’01-JAN-2001’ AND ’31-DEC-2001’ AND gpa > 3.0;

  4. SELECT student_id, gpa FROM student_grades

    WHERE semester_end BETWEEN ’01-JAN-2001’ AND ’31-DEC-2001’ OR gpa > 3.0;

  5. SELECT student_id, gpa FROM student_grades

WHERE semester_end > ’01-JAN-2001’ OR semester_end < ’31-DEC-2001’ AND gpa

>= 3.0;


Answer: C

QUESTION: 253

For which action can you use the TO_DATE function?


  1. Convert any date literal to a date

  2. Convert any numeric literal to a date

  3. Convert any character literal to a date

  4. Convert any date to a character literal

  5. Format ’10-JAN-99’ to ‘January 10 1999’


Answer: C


QUESTION: 254

What is true regarding sub queries?


  1. The inner query always sorts the results of the outer query

  2. The outer query always sorts the results of the inner query

  3. The outer query must return a value to the outer query

  4. The inner query returns a value to the outer query

  5. The inner query must always return a value or the outer query will give an error


Answer: D


Explanation:

The inner query returns a value to the outer query. If the inner query does not return a value, the outer query does not return a result

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